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To determine the downward force acting on a roller along an inclined plane due to gravity and study its relationship with the angle of inclination by plotting a graph between the force and \sin \theta.
When an object is placed on an inclined plane, the gravitational force acting on the object can be resolved into two components:
The parallel component of the gravitational force can be calculated using:
F_{\parallel} = mg \sin \theta
where:
Set up the inclined plane:
Measure the mass of the roller:
Attach the spring balance:
Measure the angle of inclination:
Measure the force:
Repeat for different angles:
Plot the graph:
| Angle θ\thetaθ (°) | sinθ\sin \thetasinθ | Force FFF (N) |
|---|---|---|
| 10° | sin10∘\sin 10^\circsin10∘ | Measured force |
| 20° | sin20∘\sin 20^\circsin20∘ | Measured force |
| 30° | sin30∘\sin 30^\circsin30∘ | Measured force |
| 40° | sin40∘\sin 40^\circsin40∘ | Measured force |
| 50° | sin50∘\sin 50^\circsin50∘ | Measured force |
| 60° | sin60∘\sin 60^\circsin60∘ | Measured force |
| … | … | … |
This experiment helps demonstrate the direct relationship between the component of gravitational force and the angle of inclination, as well as the principles of force resolution in inclined plane problems.
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Not included ,Weight Box 100gm |
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